Purcent in Graph Histogramme

[#1]

Hello,

I want to express my graph in purcent, but I don't know how to do.

Thank's.

[#2]

[#3]

Thanks,

but my problème is that I make a "Count(IdCourse)" to generate my graph like this :

[#4]

tchicken wrote:
Thanks,
but my problème is that I make a "Count(IdCourse)" to generate my graph like this :
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[#5]

Hi tchicken,

You could use the expression = Count(IdCourse) / Count(Total IdCourse) and then do the formatting as proposed by Jay.

Regards, Sander

[#6 · Accepted solution]

It's ok thanks.