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prees959
Creator II
Creator II

Trying to Add a Ranking in Script

Hi,  I am using the following script to order and Rank a temporary table :

Ranked:

load AutoNumber([Area] & ' - ' & [DayOfWeek] & ' - ' & [Staff Type]) as Rank,

     [Area] & ' - ' & [DayOfWeek] & ' - ' & [Staff Type] as [Detail],

     sum([Total]) as [Total]

     Resident Detail_Data   

     group by  [Area],[DayOfWeek] ,[Staff Type];

When I look at this tables contents the autonumber isn't doing exactly what I intended.... the output is similar to this :

rank_version1.PNG

But, what I would ideally like to show is the following where the rank is split where the total is the same :

rank_version2.PNG

Can this be achieved??

Many thanks,

Phil

1 Solution

Accepted Solutions
sunny_talwar

May be you want this

Ranked:

LOAD AutoNumber(Total) as Rank,

     *;

LOAD [Area] & ' - ' & [DayOfWeek] & ' - ' & [Staff Type] as [Detail],

    Sum([Total]) as [Total]

Resident Detail_Data

Group By  [Area], [DayOfWeek], [Staff Type];

View solution in original post

3 Replies
sunny_talwar

May be you want this

Ranked:

LOAD AutoNumber(Total) as Rank,

     *;

LOAD [Area] & ' - ' & [DayOfWeek] & ' - ' & [Staff Type] as [Detail],

    Sum([Total]) as [Total]

Resident Detail_Data

Group By  [Area], [DayOfWeek], [Staff Type];

prees959
Creator II
Creator II
Author

Hi Sunny,

Thanks for your reply.  Unfortunately, I'm getting an error on the first part of the script

Field Not Found Total

If I comment out the first part the script runs but without the rank field...

Ranked:

//LOAD AutoNumber(Total) as Rank,

//    *;

LOAD [Area] & ' - ' & [DayOfWeek] & ' - ' & [Staff Type] as [Detail],

    Sum([Total]) as [Total]

Resident Detail_Data

Group By  [Area], [DayOfWeek], [Staff Type];

prees959
Creator II
Creator II
Author

Fixed it :

Ranked:

LOAD AutoNumber(sum(Total)) as Rank,

          [Area] & ' - ' & [DayOfWeek] & ' - ' & [Staff Type] as [Detail],

          Sum([Total]) as [Total]

Resident Detail_Data

Group By  [Area], [DayOfWeek], [Staff Type];



Thanks for your help again,

Phil