dimension label for class

[#1]

Hi,

In attached qvw file contains a barchart.

In dimesion tab:

Class(AngleTabPos,10)

In expression tab:

Count(Lenskey)

Note :User has a chance to view only 10 values(bars) at a time.

Now what i am trying to work is in dimension labels are displaying as "0<=x<10, 10<=x<20, 20<=x<30..................350<=x<360", but what i want to display is "10,20,30,...............360".

Is it possible to do this ?

Thanks in advance.

[#2]

Hi,

No its not getting what we expected. It is showing like "3739, 3939, 4339..." instead of "100,200,300,...".

I done same what you mentioned in post , but not able to get it.

Any other way to get it.

Thanks

[CELAMBARASAN]

Hi

     Can you check and tel me whats min(Lenskey) there?

[CELAMBARASAN]

Hi,

     Can you attach a image as chart with vRange(Num(Class(LensKey,100)) - vRange) variable and without vRange(Num(Class(LensKey,100)) ) variable , vRange value and Min(LensKey) value in text object.

Celambarasan

[#5]

Hi,

Min of Lenskey =1879586761

Thanks

[#6]

Hi,

Please find the attached images of "WithvRange" , "WithOutvRange", "vRange", "Min(Lenskey)" values.

Thanks

[CELAMBARASAN]

Hi,

Check with this

      vRange  with value "=((floor(Min({1}Lenskey)/100)*100)-100)"

Use dimension expression like this Num(Class(LensKey,100)) - vRange

Hope it helps

Celambarasan

[#8]

Hi,

No, it is displaying like 3800, 4000, 4400, 4700...........

Thanks

[CELAMBARASAN]

Hi,

     Have you done any selection or ignored selection in your expression?

[#10]

Hi,

i used single expression as seen below :

=Count({$<DefectName={"Defect.EdgeChip"}>} LensKey)/Count({$<DefectName={"Defect.EdgeChip"}>} TOTAL LensKey)

Thanks

[CELAMBARASAN · Accepted solution]

Hi,

Then add that set analysis expr to the min

      vRange  with value "=((floor(Min({$<DefectName={'Defect.EdgeChip'}>} Lenskey)/100)*100)-100)"

     Use dimension expression like this Num(Class(LensKey,100)) - vRange

Hope it helps

Celambarasa