group by or cluster?

[cscherer]

Hello,

I've got a problem with clustering data. I've got dates and orders and I want to know in the first steps, how many orders I've got per day - this works. In the second step, I want to know how many days I've got with 1-5 orders, 6-10 orders and so on.

It shall look like this:

I attached the .qvw

Thanks in advance,

Clemens

[cscherer]

here is the picture:

[#3]

try

if(count(distinct order)<=5,'5',if(count(distinct order)<=10,'10','Other')) as dimension

[cscherer]

thank you, but that is not what I mean. I need the "next step"

15 times <= 5

11 times <=10

...

[#5]

if(count(distinct order)<=5,'5',if(count(distinct order)<=10,'10',if(count(distinct order)<=20,'20','>20')))) as dimension

[#6]

or:

if(count(distinct order)<=5,'Days with 1 to 5 orders',if(count(distinct order)<=10,'Days with 6 to 10 orders ',if(count(distinct order)<=20,'Days with 11 to 20 orders','days with >20 orders')))) as dimension

[cscherer]

it doesn't work. have you got the .qvw?

[#8 · Accepted solution]

ok try this:

Load Script:

Orders:

LOAD order,

     date,

     article

FROM

C:\test.xls

(biff, embedded labels, table is Sheet1$);

Summary:

Left Join(Orders)

Load date,

          if(count(distinct order)<=5,

                    'days with 1 to 5 orders',

          if(count(distinct order)<=10,

                    'days with 6 to 10 orders',

          if(count(distinct order)<=20,

                    'days with 11 to 20 orders',

          'days with >20 orders'))) as  DayType

resident Orders group by date;

Table:

DayType as dimension

count(distinct date) as Expression

[cscherer]

that`s it! thank you so much!

[cscherer]

Hello,

one more question: is it possible to intricate more than 7 if-formulas? If not, I think I`ll need another solution for my problem...

Thanks,

regards,

cs