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Hi Team,

LCPC
AGRA28
AHMEDABAD38
AHMEDNAGAR41
AHMEDNAGAR41
AHMEDNAGAR42
AIZWAL79
AJC BOSE RD70
AMRAVATI44
AMRELI35
AMRELI36


Above is the sample data. I have to find out LCs appearing in different PC eg in above sample data Ahmednagar and Amreli are two LCs where PCs are different.

I can use Peek function for this, eg.

Load LC,PC
Resident Sample_Data
Where LC = Peek(LC) And PC <> Peek(PC);

But there is one problem with this is that i will have only

AHMEDNAGAR42
AMRELI36


means where LC is same and PC is different.

But for comparison, I want the output as below:

AHMEDNAGAR41
AHMEDNAGAR42
AMRELI35
AMRELI36


means all distinct records where PCs are different.

Any suggestion!!

I know the use of Where Not Exist(LC) but can i use eg.

Where Not Exist (LC) And Not Exist (PC)
OR Not Exist (LC.PC)

2 Replies
Not applicable
Author

I was thinking you could combine LC and PC to create a unique key and just not load the one that are found more than once.

tmp:

LOAD

LC&' '&PC as ID,

LC,

PC

Resident Sample_Data;

myTable:

noconcatenate load

ID,

LC,

PC

resident tmp where ID <> peek(ID);

drop table tmp;



Good luck!

BR,

Ida



johnw
Champion III
Champion III

How about this?

LOAD LC
FROM data source
WHERE LC = peek(LC)
AND PC <> peek(PC)
ORDER BY LC, PC
;
LEFT JOIN
LOAD LC, PC
FROM data source
;