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see attachment
aggr(min(if(due > 0,due)),code)
why doesnt this work?
i need there the code-value from the corresponding min(if(due > 0,due).
Gives me all '-' cause there are many answers ... while there only should be one
empty message scar .. did i miss anything?
bump
Hi Amien,
That's not that it doesn't work. In fact, the '-' character here means that you have several values. Try the following expression and you'll see that I'm right.
= Concat( Aggr( Min( If( due > 0, due ) ), code ), ', ' )
Here, I just concatenated the list returned by your expression.
I hope that'll answer your question.
Best regards,
Franck SEREGAZA
Business & Decision
"Gives me all '-' cause there are many answers ... while there only should be one"
but then i have the wrong expression
cause i need the code (and that is only one) where min(if(due > 0,due)) is the lowest .. based on filenumber and value
so .. where min(if(due > 0,due)) is the lowest (within the same filenumber) .. i need that code .. and that can only be one
see attachment ..
on filenumber 1 .. and value = 200, due = 4 is the lowest
on filenumber 1... and value = 300 , due = 5 is the lowest
so, i need this output:
1, 200, 4, 002
1, 300, 5, 002
1, 500, 4, 004
1, 100, 4 005
2, 100, 28, 202
Sorry Amien, I didn't correctly read your post. Try this one:
=concat({$<due={'$(=min(if(due>0, due)))'}>} distinct code, ', ')
It works with your current data, but what if you have more "due" values above 0. Try and tell me.
Best regards,
Franck SEREGAZA
Business & Decision
Don't bother. It doesn't work (I just get too tired to see the right column). Sorry.
Best regards,
Franck SEREGAZA
Business & Decision
Sorry for keeping you waiting, but I've finally found out the solution to your problem. Use the "FirstSortedValue" function:
=FirstSortedValue(code, if(due>0, due))
I'm pretty sure, but if I'm wrong, keep me informed.
Best regards,
Franck SEREGAZA
Business & Decision