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Hi!
I have a new problem. This is my table:
My first expressiong is : Count({$<State={'Processed','Cancelled'},Failed={'Closed','Failed'}>} RORequest)
I need to find the % of Total request for all the Hours using the condition of the first expession.
Or may be I can find the % using the column total? but how can i use the name of thi column in my expression?
Count(TOTAL <[Kind RO]> {$<State={'Processed','Cancelled'},Failed={'Closed','Failed'}>} RORequest)
Try this:
=Count({$<State={'Processed','Cancelled'},Failed={'Closed','Failed'}>} RORequest)/Count(TOTAL {$<State={'Processed','Cancelled'},Failed={'Closed','Failed'}>} RORequest)
Best,
Sunny
It's not working, it gives me the total number of all the requests. But I need the total quantity of requests according to the dimension KIND RO
Not sure what would be the difference between total number and total quantity? In the above image you posted can you point out what the total number vs. total quantity is?
Best,
Sunny
Hi,
Try with ALL or 1
like,
Count({$<State={'Processed','Cancelled'},Failed={'Closed','Failed'}>} RORequest)/Count({1<State={'Processed','Cancelled'},Failed={'Closed','Failed'}>} RORequest)
or
Count({$<State={'Processed','Cancelled'},Failed={'Closed','Failed'}>} RORequest)/Count(TOTAL {<State={'Processed','Cancelled'},Failed={'Closed','Failed'}>} RORequest)
Regards
I mean that the result of this formula is 268, that is the total quantity of all the requests, and what I need is the total quantity of requests of each Kind RO, like Allocation requests has 175 ,Availability requests has 5 and so on.
But the column that has this numbers is just a partial sum of Pivot Table.
Give this a try:
=Count({$<State={'Processed','Cancelled'},Failed={'Closed','Failed'}>} RORequest)/Count(TOTAL <KIND RO> {$<State={'Processed','Cancelled'},Failed={'Closed','Failed'}>} RORequest)
Hi Max,
I think i havent written all the requirements properly. I need total quantity of each KIND RO.
Count(TOTAL <[Kind RO]> {$<State={'Processed','Cancelled'},Failed={'Closed','Failed'}>} RORequest)
That works perfectly!!! Thanks!!!