AND operator in set analysis

[Anonymous]

Hi all,

     I have a pivot table as in the image below, but there's one exception only for AMS (row dim), when the role = 'Guarantee' (the role is not in the pivot), so I should remove those from the "QD" count. But how do I include that in the set analysis to say "where region<>'AMS' AND role<>'Gaurantee' " without loosing the whole AMS row?

=Count({<[Report Date]={"$(MaxDate)"}>} [StatusID])

[datanibbler]

Hi Oscar,

you need no AND inside a set_expression. Just separate several set_expressions with a comma.

[Anonymous]

Hi DataNibbler,

That doesn't work because it will match/remove any coincidence, if for example I write this

=Count({<[Report Date]={"$(MaxDate)"},REGION-={"AMS"},ROLE-={"Guarantee"}>} [StatusID])

In the pivot table, I'll missing any AMS data and all data with "guarantee" role

[stigchel]

You can use the Set Modifier P (possible), which in below example gives a list of possible id's that meet your criteria

=Count({<[Report Date]={"$(MaxDate)"},[Id]=P({1<Region={'<>AMS'},Role={'<>Guarantee'}>} [Id])>} [StatusID])

[gmoraleswit]

Do you have the Guarantee role only in the AMS region? Try this:

=Count({<[Report Date]={"$(MaxDate)"},role-={'Guarantee'}>} [StatusID])

If you have the role in other regions and you want to exclude it only for the AMS region then you might need to use an if in your expression:

if(region = AMS, Count({<[Report Date]={"$(MaxDate)"},role-={'Guarantee'}>} [StatusID]), Count({<[Report Date]={"$(MaxDate)"}>} [StatusID]))

or create a new field in your script:

load

..

if(region=AMS and role='Gaurantee', 0, 1) as flag_validRecord

from...

then in your expression:

Count({<[Report Date]={"$(MaxDate)"},flag_validRecord={1}>} [StatusID])

[jaimeaguilar]

Hi,

maybe like this:

=Count({<[Report Date]={"$(MaxDate)"}, Region-={'AMS'}, Role-={'Guarantee'}>} [StatusID])

use -= to exclude values from set analysis

regards

[Anonymous]

Try this and confirm

=Count({<[Report Date]={"$(MaxDate)",Region-='AMS',Role-='Gaurantee'}>} [StatusID])

[Anonymous]

Happend what I thought, AMS QD value is 0, it should not

[Anonymous]

Thanks Piet but it didn't work, I tried E() instead of P() and I get a very similar result of what I'm looking for, but still is not the answer.

[Anonymous]

hi Gabriela, I just wanted to find a way to do it with set analysis