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SMahadevan1608028474
Contributor
Contributor

Execution failed : Job execution failed (Java)

Talend application is installed in below path,

C:\temp\TOS_DI-Win32-20200219_1130-V7.3.1

 

Execution failed : Job execution failed.

[Cannot run program "C:/Program Files/Java/jre1.8.0_271/bin/java.exe" (in directory "C:\temp\TOS_DI-Win32-20200219_1130-V7.3.1\workspace\DATAVALIDATION_JAN11\poms\jobs\process\datavalidation_filter_v1_3_tconvertype_0.1\src\main\ext-resources"): CreateProcess error=2, The system cannot find the file specified]

 

Do I need to install the Java where the Talend is installed?

 

When I run the below statement in command prompt I am not getting the Output path for Java installation folder.

echo %JAVA_HOME%

%JAVA_HOME%

 

Also , i have checked java installed or not in cmd) java -version

java version "1.8.0_281"

Java(TM) SE Runtime Environment (build 1.8.0_281-b09)

Java HotSpot(TM) 64-Bit Server VM (build 25.281-b09, mixed mode)

 

 

Labels (2)
2 Replies
SMaru
Contributor
Contributor

a.     Go to control panel and search for System (Alternatively right click on My Computer and go to properties)

b.     Go to Advanced System Settings

c.     Environment Variables

d.     In the lower portion for system make the following changes

e.     Add JAVA_HOME with value ( JAVA installation path) it can be anywhere in your system.

f.      Edit Path and add new value ( add Java Path varaible in Path)

Create a new system variable below with the listed value:

JAVA_HOME: C:\Program Files\Java\jdk-11.0.7

 

Edit the existing path value to add a new entry listed below:

PATH: %JAVA_HOME%\bin

SMahadevan1608028474
Contributor
Contributor
Author

Thanks for your solution and the issue get fixed.