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 swarup_malli
		
			swarup_malli
		
		
		
		
		
		
		
		
	
			
		
		
			
					
		
Hi All,
There is a floor with the dimension 141 * 50 ( lenght * breath).
I want to create a table that resembles the above floor wihth 141 columns and 50 rows.
The column should start with A,B........AB,AC.......so on and the rows should start from 1 to 50.
In essence I'm trying to create a grid using a table object
 
					
				
		
 lblumenfeld
		
			lblumenfeld
		
		
		
		
		
		
		
		
	
			
		
		
			
					
		Are you trying to always explicitly generate the floor diagram with these dimensions? If so then the script below will generate a table called FloorDiagram. This contains the data for your 50 x 141 cell grid.
Then create a Pivot Table as follows:
I've attached a partial screen shot of the resulting pivot table and the data and sorting sections.
Here is the script.
CharMap:
Mapping Load * Inline [
Num, Char
01,A
02,B
03,C
04,D
05,E
06,F
07,G
08,H
09,I
10,J
11,K
12,L
13,M
14,N
15,O
16,P
17,Q
18,R
19,S
20,T
21,U
22,V
23,W
24,X
25,Y
26,Z
];
Columns:
Load 
    1 as Key,
    If(RowNo() < 27,
        MapSubString('CharMap',
	    If(RowNo() < 10,
    	        '0' & RowNo(),
        	    RowNo()
             )
        ),	
	MapSubString('CharMap',
	    If(Floor(RowNo() / 26) - If(Mod(RowNo(), 26) = 0, 1, 0) < 10,
    	      '0' & (Floor(RowNo() / 26) - If(Mod(RowNo(), 26) = 0, 1, 0)),
              Floor(RowNo() / 26) - If(Mod(RowNo(), 26) = 0, 1, 0)
              )
        ) &
	MapSubString('CharMap', 
	    If(Mod(RowNo(), 26) < 10,
    	      '0' & (Mod(RowNo(), 26) + If(Mod(RowNo(), 26) = 0, 1, 0)),
              Mod(RowNo(), 26)
              )
        )
     ) as ColCode,
     RowNo() as ColOrder
AutoGenerate 141;
FloorDiagram:
Load
    RowNo() as RowNum,
    1 as Key
AutoGenerate 50;
FloorDiagram:
Left Join (FloorDiagram)
Load 
    Key,
    Dual(ColCode, ColOrder) as ColCode
Resident Columns;
Drop Field Key From FloorDiagram;
Drop Table Columns;
					
				
			
			
				
			
			
			
				
			
			
			
			
			
		 
					
				
		
 lblumenfeld
		
			lblumenfeld
		
		
		
		
		
		
		
		
	
			
		
		
			
					
		Are you trying to always explicitly generate the floor diagram with these dimensions? If so then the script below will generate a table called FloorDiagram. This contains the data for your 50 x 141 cell grid.
Then create a Pivot Table as follows:
I've attached a partial screen shot of the resulting pivot table.
Here is the script.
CharMap:
Mapping Load * Inline [
Num, Char
01,A
02,B
03,C
04,D
05,E
06,F
07,G
08,H
09,I
10,J
11,K
12,L
13,M
14,N
15,O
16,P
17,Q
18,R
19,S
20,T
21,U
22,V
23,W
24,X
25,Y
26,Z
];
Columns:
Load 
    1 as Key,
    If(RowNo() < 27,
        MapSubString('CharMap',
	    If(RowNo() < 10,
    	        '0' & RowNo(),
        	    RowNo()
             )
        ),	
	MapSubString('CharMap',
	    If(Floor(RowNo() / 26) - If(Mod(RowNo(), 26) = 0, 1, 0) < 10,
    	      '0' & (Floor(RowNo() / 26) - If(Mod(RowNo(), 26) = 0, 1, 0)),
              Floor(RowNo() / 26) - If(Mod(RowNo(), 26) = 0, 1, 0)
              )
        ) &
	MapSubString('CharMap', 
	    If(Mod(RowNo(), 26) < 10,
    	      '0' & (Mod(RowNo(), 26) + If(Mod(RowNo(), 26) = 0, 1, 0)),
              Mod(RowNo(), 26)
              )
        )
     ) as ColCode,
     RowNo() as ColOrder
AutoGenerate 141;
FloorDiagram:
Load
    RowNo() as RowNum,
    1 as Key
AutoGenerate 50;
FloorDiagram:
Left Join (FloorDiagram)
Load 
    Key,
    Dual(ColCode, ColOrder) as ColCode
Resident Columns;
Drop Field Key From FloorDiagram;
Drop Table Columns;
					
				
			
			
				
			
			
			
				
			
			
			
			
			
		 
					
				
		
 lblumenfeld
		
			lblumenfeld
		
		
		
		
		
		
		
		
	
			
		
		
			
					
		Here is the attachment. The editor wasn't letting me add it to the prior post.
 
					
				
		
 marcus_sommer
		
			marcus_sommer
		
		
		
		
		
		
		
		
	
			
		
		
			
					
		If you don't need just a two column-table which you expand within a pivot else a real table within the datamodel you could use something like this:
t1: load *, 1 as ID, chr(64 + if(Cluster = 1, null(), Cluster -1)) &
chr(64 + recno() - ((Cluster - 1) * 26)) as Column; load ceil(recno() / 26) as Cluster autogenerate 141; t2: generic load 1 as ID, recno() as Row, 'X' as Dummy autogenerate 50; for i = nooftables() to 0 step -1 let vTable = tablename($(i)); if left('$(vTable)', 2) = 't2' then left join (t1) load * resident $(vTable); drop tables $(vTable); end if next
- Marcus
 albert_guito
		
			albert_guito
		
		
		
		
		
		
		
		
	
			
		
		
			
					
		 
					
				
		
 lblumenfeld
		
			lblumenfeld
		
		
		
		
		
		
		
		
	
			
		
		
			
					
		Are you trying to always explicitly generate the floor diagram with these dimensions? If so then the script below will generate a table called FloorDiagram. This contains the data for your 50 x 141 cell grid.
Then create a Pivot Table as follows:
I've attached a partial screen shot of the resulting pivot table and the data and sorting sections.
Here is the script.
CharMap:
Mapping Load * Inline [
Num, Char
01,A
02,B
03,C
04,D
05,E
06,F
07,G
08,H
09,I
10,J
11,K
12,L
13,M
14,N
15,O
16,P
17,Q
18,R
19,S
20,T
21,U
22,V
23,W
24,X
25,Y
26,Z
];
Columns:
Load 
    1 as Key,
    If(RowNo() < 27,
        MapSubString('CharMap',
	    If(RowNo() < 10,
    	        '0' & RowNo(),
        	    RowNo()
             )
        ),	
	MapSubString('CharMap',
	    If(Floor(RowNo() / 26) - If(Mod(RowNo(), 26) = 0, 1, 0) < 10,
    	      '0' & (Floor(RowNo() / 26) - If(Mod(RowNo(), 26) = 0, 1, 0)),
              Floor(RowNo() / 26) - If(Mod(RowNo(), 26) = 0, 1, 0)
              )
        ) &
	MapSubString('CharMap', 
	    If(Mod(RowNo(), 26) < 10,
    	      '0' & (Mod(RowNo(), 26) + If(Mod(RowNo(), 26) = 0, 1, 0)),
              Mod(RowNo(), 26)
              )
        )
     ) as ColCode,
     RowNo() as ColOrder
AutoGenerate 141;
FloorDiagram:
Load
    RowNo() as RowNum,
    1 as Key
AutoGenerate 50;
FloorDiagram:
Left Join (FloorDiagram)
Load 
    Key,
    Dual(ColCode, ColOrder) as ColCode
Resident Columns;
Drop Field Key From FloorDiagram;
Drop Table Columns;
 
					
				
		
 lblumenfeld
		
			lblumenfeld
		
		
		
		
		
		
		
		
	
			
		
		
			
					
		Are you trying to always explicitly generate the floor diagram with these dimensions? If so then the script below will generate a table called FloorDiagram. This contains the data for your 50 x 141 cell grid.
Then create a Pivot Table as follows:
I've attached a partial screen shot of the resulting pivot table and the data and sorting sections.
Here is the script.
CharMap:
Mapping Load * Inline [
Num, Char
01,A
02,B
03,C
04,D
05,E
06,F
07,G
08,H
09,I
10,J
11,K
12,L
13,M
14,N
15,O
16,P
17,Q
18,R
19,S
20,T
21,U
22,V
23,W
24,X
25,Y
26,Z
];
Columns:
Load 
    1 as Key,
    If(RowNo() < 27,
        MapSubString('CharMap',
	    If(RowNo() < 10,
    	        '0' & RowNo(),
        	    RowNo()
             )
        ),	
	MapSubString('CharMap',
	    If(Floor(RowNo() / 26) - If(Mod(RowNo(), 26) = 0, 1, 0) < 10,
    	      '0' & (Floor(RowNo() / 26) - If(Mod(RowNo(), 26) = 0, 1, 0)),
              Floor(RowNo() / 26) - If(Mod(RowNo(), 26) = 0, 1, 0)
              )
        ) &
	MapSubString('CharMap', 
	    If(Mod(RowNo(), 26) < 10,
    	      '0' & (Mod(RowNo(), 26) + If(Mod(RowNo(), 26) = 0, 1, 0)),
              Mod(RowNo(), 26)
              )
        )
     ) as ColCode,
     RowNo() as ColOrder
AutoGenerate 141;
FloorDiagram:
Load
    RowNo() as RowNum,
    1 as Key
AutoGenerate 50;
FloorDiagram:
Left Join (FloorDiagram)
Load 
    Key,
    Dual(ColCode, ColOrder) as ColCode
Resident Columns;
Drop Field Key From FloorDiagram;
Drop Table Columns;
					
				
			
			
				
			
			
			
			
			
			
			
		 
					
				
		
 lblumenfeld
		
			lblumenfeld
		
		
		
		
		
		
		
		
	
			
		
		
			
					
		Are you trying to always explicitly generate the floor diagram with these dimensions? If so then the script below will generate a table called FloorDiagram. This contains the data for your 50 x 141 cell grid.
Then create a Pivot Table as follows:
I've attached a partial screen shot of the resulting pivot table and the data and sorting sections.
Here is the script.
CharMap:
Mapping Load * Inline [
Num, Char
01,A
02,B
03,C
04,D
05,E
06,F
07,G
08,H
09,I
10,J
11,K
12,L
13,M
14,N
15,O
16,P
17,Q
18,R
19,S
20,T
21,U
22,V
23,W
24,X
25,Y
26,Z
];
Columns:
Load 
    1 as Key,
    If(RowNo() < 27,
        MapSubString('CharMap',
	    If(RowNo() < 10,
    	        '0' & RowNo(),
        	    RowNo()
             )
        ),	
	MapSubString('CharMap',
	    If(Floor(RowNo() / 26) - If(Mod(RowNo(), 26) = 0, 1, 0) < 10,
    	      '0' & (Floor(RowNo() / 26) - If(Mod(RowNo(), 26) = 0, 1, 0)),
              Floor(RowNo() / 26) - If(Mod(RowNo(), 26) = 0, 1, 0)
              )
        ) &
	MapSubString('CharMap', 
	    If(Mod(RowNo(), 26) < 10,
    	      '0' & (Mod(RowNo(), 26) + If(Mod(RowNo(), 26) = 0, 1, 0)),
              Mod(RowNo(), 26)
              )
        )
     ) as ColCode,
     RowNo() as ColOrder
AutoGenerate 141;
FloorDiagram:
Load
    RowNo() as RowNum,
    1 as Key
AutoGenerate 50;
FloorDiagram:
Left Join (FloorDiagram)
Load 
    Key,
    Dual(ColCode, ColOrder) as ColCode
Resident Columns;
Drop Field Key From FloorDiagram;
Drop Table Columns;
					
				
			
			
				
			
			
			
			
			
			
			
		 
					
				
		
 lblumenfeld
		
			lblumenfeld
		
		
		
		
		
		
		
		
	
			
		
		
			
					
		Are you trying to always explicitly generate the floor diagram with these dimensions? If so then the script below will generate a table called FloorDiagram. This contains the data for your 50 x 141 cell grid.
Then create a Pivot Table as follows:
I've attached a partial screen shot of the resulting pivot table.
Here is the script.
CharMap:
Mapping Load * Inline [
Num, Char
01,A
02,B
03,C
04,D
05,E
06,F
07,G
08,H
09,I
10,J
11,K
12,L
13,M
14,N
15,O
16,P
17,Q
18,R
19,S
20,T
21,U
22,V
23,W
24,X
25,Y
26,Z
];
Columns:
Load 
    1 as Key,
    If(RowNo() < 27,
        MapSubString('CharMap',
	    If(RowNo() < 10,
    	        '0' & RowNo(),
        	    RowNo()
             )
        ),	
	MapSubString('CharMap',
	    If(Floor(RowNo() / 26) - If(Mod(RowNo(), 26) = 0, 1, 0) < 10,
    	      '0' & (Floor(RowNo() / 26) - If(Mod(RowNo(), 26) = 0, 1, 0)),
              Floor(RowNo() / 26) - If(Mod(RowNo(), 26) = 0, 1, 0)
              )
        ) &
	MapSubString('CharMap', 
	    If(Mod(RowNo(), 26) < 10,
    	      '0' & (Mod(RowNo(), 26) + If(Mod(RowNo(), 26) = 0, 1, 0)),
              Mod(RowNo(), 26)
              )
        )
     ) as ColCode,
     RowNo() as ColOrder
AutoGenerate 141;
FloorDiagram:
Load
    RowNo() as RowNum,
    1 as Key
AutoGenerate 50;
FloorDiagram:
Left Join (FloorDiagram)
Load 
    Key,
    Dual(ColCode, ColOrder) as ColCode
Resident Columns;
Drop Field Key From FloorDiagram;
Drop Table Columns;
					
				
			
			
				
			
			
			
			
			
			
			
		 
					
				
		
 lblumenfeld
		
			lblumenfeld
		
		
		
		
		
		
		
		
	
			
		
		
			
					
		Here is the attachment. The editor wasn't letting me add it to the prior post.
 
					
				
		
 marcus_sommer
		
			marcus_sommer
		
		
		
		
		
		
		
		
	
			
		
		
			
					
		If you don't need just a two column-table which you expand within a pivot else a real table within the datamodel you could use something like this:
t1: load *, 1 as ID, chr(64 + if(Cluster = 1, null(), Cluster -1)) &
chr(64 + recno() - ((Cluster - 1) * 26)) as Column; load ceil(recno() / 26) as Cluster autogenerate 141; t2: generic load 1 as ID, recno() as Row, 'X' as Dummy autogenerate 50; for i = nooftables() to 0 step -1 let vTable = tablename($(i)); if left('$(vTable)', 2) = 't2' then left join (t1) load * resident $(vTable); drop tables $(vTable); end if next
- Marcus
 
					
				
		
 swarup_malli
		
			swarup_malli
		
		
		
		
		
		
		
		
	
			
		
		
			
					
		Thank you Guys..appreciate your help.I'll get back to you all after testing the code
 
					
				
		
 swarup_malli
		
			swarup_malli
		
		
		
		
		
		
		
		
	
			
		
		
			
					
		Worked like a charm. Thank you guys for the help.
