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Asiolinka
Contributor II
Contributor II

Check for letters/numbers pattern

Hi All,

I need to write two patterns check:

LLLNNNNNN - 3 letters + 6 numbers

AND

LLNNNNNNN -2 letters + 7 numbers. 

I should have results as below  (need to obtain 'flag' field):

 

field1 flag
ABC123456 0
*BC123456 1
AB/123456 1
AB1234567 0
A*123456 1
AB12CD56 1

 

I tried to use:

(-(len(FIELD)=9 and istext(Left(FIELD,2)) and isnum(right(FIELD,7)))) BUT I saw special characters in results which is not correct. 

Could you please help? 

Labels (1)
2 Solutions

Accepted Solutions
Chanty4u
MVP
MVP

Try this 

if(  match(FIELD, '^[A-Z]{3}\d{6}$') and len(FIELD)=9,    0,    1) asflag

View solution in original post

Kushal_Chawda

@Asiolinka  try below

Data:
Load *,
if(len(Field)=9,
if((len(KeepChar(Left(lower(Field),3),'abcdefghijklmnopqrstuvwxyz'))=3 and 
 isnum(right(Field,6))) or
(len(KeepChar(Left(lower(Field),2),'abcdefghijklmnopqrstuvwxyz'))=2 
and isnum(right(Field,7))),0,1),1) as Flag 
Inline [
Field
ABC123456
*BC123456
AB/123456
AB1234567
A*123456
AB12CD56 ];
 

View solution in original post

6 Replies
N30fyte
Creator
Creator

'A*123456' has 8 characters, 'AB12CD56' does not follow either pattern. Are they valid results?

Asiolinka
Contributor II
Contributor II
Author

sorry, every single time it should have 9 char, please see below:

field1 flag
ABC123456 0
*BC123456 1
AB/123456 1
AB1234567 0
A*1234567 1
AB12CD567 1

 

N30fyte
Creator
Creator

The patterns in your original post are

LLLNNNNNN

and

LLNNNNNNN

The last row in your data is AB12CD567

which is

LLNNLLNNN

In the fourth row of your table, AB1234567 follows the second pattern but is flagged 0.

In the fifth row of your table , A*1234567 also follows the second pattern but is flagged 1.

Can you be more clear about your requirements?

 

 

Chanty4u
MVP
MVP

Try this 

if(  match(FIELD, '^[A-Z]{3}\d{6}$') and len(FIELD)=9,    0,    1) asflag

Kushal_Chawda

@Asiolinka  try below

Data:
Load *,
if(len(Field)=9,
if((len(KeepChar(Left(lower(Field),3),'abcdefghijklmnopqrstuvwxyz'))=3 and 
 isnum(right(Field,6))) or
(len(KeepChar(Left(lower(Field),2),'abcdefghijklmnopqrstuvwxyz'))=2 
and isnum(right(Field,7))),0,1),1) as Flag 
Inline [
Field
ABC123456
*BC123456
AB/123456
AB1234567
A*123456
AB12CD56 ];
 
Asiolinka
Contributor II
Contributor II
Author

Thank you! Everything is now totaly clear.