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Anonymous
Not applicable

Annotated with variable function.

Has anyone realized that if you talked about some part of a function inside a variable, it can not work?

Had a problem in one variable and could not identify the error. I noticed that within my function was variable and log below was another part of the formula was no longer being used and was discussed.

Because of this, she was not working. After deleting the formula that was commented she went to work.

Does anyone know the reason why?

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