Announcements
cancel
Showing results for
Did you mean:
Creator

## Calculating possible values

Hi All,

I've been trying to solve this mystery for a while now.

I have a list of customers with their proposed Discount code and their discount codes used at transaction. So my end goal is to find the number of customers by month who have been using the proposed discount code (among multiple transaction discount codes if used).

sum(aggr(if(ProposedDiscCode= Concat(DISTINCT Transaction_Discount_Code, ','),1,0),Customer,Month,Store))

The above formula helps me identify the number but when the customer uses only the proposed discount code and none others.

CustomerProposedDiscCodeTransaction_Discount_Code
SnehaIHIH
TimIGIG
JoeIFIF,IG,IY

So my formula for the above table of values gives the count as 2, whereas I want 4.

S

1 Solution

Accepted Solutions
MVP

If this is how your data is, then try this

=Count(DISTINCT If(Transaction_Discount_Code = ProposedDiscCode, Customer))

10 Replies
MVP

May be try this

Sum(If(SubStringCount(Transaction_Discount_Code, ProposedDiscCode) > 0, 1, 0))

MVP

or this

Sum(If(Index(Transaction_Discount_Code, ProposedDiscCode), 1, 0))

Creator
Author

Hi Sunny,

Can the expression be enabled to look at distinct transaction discount codes used? because in a month they may have multiple transactions and your formula calculates it at that level.

Thanks

S

MVP

I am not sure I understand... but may be this

Sum(Aggr(If(SubStringCount(Transaction_Discount_Code, ProposedDiscCode) > 0, 1, 0), Customer, Month, Store))

Creator
Author

Hi Sunny,

It gives the same value as my expression above.

MVP

Would you be able to provide a sample where you have Month and Store with expected output from the sample provided?

Creator
Author

Hi Sunny,

I have given a sample data.

My formula gives the total correct disc code customers to be 5, but the actual correct discount code customers should be 9.

MVP

If this is how your data is, then try this

=Count(DISTINCT If(Transaction_Discount_Code = ProposedDiscCode, Customer))

Creator
Author

Hi Sunny,

This formula works.:) many thanks for helping me so quick.!