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What I have is a straight table with links to photos. If the photos do not exist, I leave the field blank. What I want to do is that if the link is good, I want to display a picture of a green camera. If the link is bad, I want to display a picture of a red camera, but I want to be able to click on the green camera and open the photo. Is this possible?
Hi Andrea,
try this:
if(only(Photo)<>0,' ','
if(only(Photo='Good'),'green camera','red camera picture')
This is what I have right now. The problem is that I want that link to be associated with the camera so when I click on the camera, it opens up the link.
I am afraid you can have either link and not picture. Or a picture without a link.