Qlik Community

Ask a Question

QlikView App Dev

Discussion Board for collaboration related to QlikView App Development.

Announcements
Live chat with experts, bring your API Integration questions. June 15th, 10 AM ET. REGISTER TODAY
cancel
Showing results for 
Search instead for 
Did you mean: 
Not applicable

How to display extra record?

Hi All,

I have a field with unique, but it has more than one record, there i need to display how many more than one  records or there for that field.

1 Solution

Accepted Solutions
swuehl
MVP
MVP

In addition to my above post, if you want to show the number of duplicates, just create a straight table chart with dimension id and as expression

=sum(Flag)

View solution in original post

17 Replies
mambi
Creator III
Creator III

=count(distinct YourFieldName)

parthiband
Partner
Partner

can u please explain a bit?

Because, Count (DISTINCT FieldName) will always return the unique records (Text Object).

But if u want in some other object it might vary.

So explain, in which object/place u want to showcase the distinct values and in what case.

Thanks,

mambi
Creator III
Creator III

Count (DISTINCT FieldName) works also on other objects like charts ...

if you've an exemple it's will be easier to explain

its_anandrjs

Elaborate more about your query

And Suppose you count any field and there are multiple records then in a straight table take dimension and Count(Dimension)

Eg:-

ID

1

1

1

2

2

3

3

3

3

Dim:- ID

Expr:-Count(ID)

Expr:- Count(DISTINCT ID) //For unique records

parthiband
Partner
Partner

I think, you may be wrong in cases like, you have a dimensions in straight table with ur field name and dates(Attendance date/ Order dates).

It cannot be unique.

The ur field might be applicable for both dates, right?

So john, its better if u explain us a bit.

mambi
Creator III
Creator III

expressions can't be used with straight table

PrashantSangle

Hi,

If you want show count of all records from same List Box

and want to show count of all records other than current selection then use

Indirect Set analysis Like

=count(DISTINCT {<FieldName=e(FieldName)>}FieldName)

Or if you want to show count of Other List Box Depend on current selection of List box

Then use

=Count (DISTINCT FieldName)


Regards,

Great dreamer's dreams never fulfilled, they are always transcended.
maxgro
MVP
MVP

if I understand your question

sum(if( aggr(count(field),field)>1,1))

1.png

Not applicable
Author

Thank you Mambi Badi. count(distinct YourFieldName) gives you Distict records count. but what i want the records which are extra for these field atrributes.

ex:   id    value

       101  axe

       101  box

       101   car

       102   pen

        103  axe

       102   car   

out put:  i am expecting:       id   value

                                          101  box

                                          101  car

                                           102 car.