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How to find maximum value of an aggregated expression?

Hi All

I have the following graph with

Dimensions: Country, GLOBAL_ITEM_ID and Yr_Wk_Frcst and I need to output the maximum value of the 2 expressions in a texbox:

I need edit below expression to retrieve maximum value 8605 of Expression number 1:

sum({<Period_Week_Counter={">=$(=max(Period_Week_Counter)-2) <$(=max(Period_Week_Counter))"}, OPE_WEK=, OPE_YY=>}Aggr(sum({<Period_Week_Counter={">=$(=max(Period_Week_Counter)-2) <$(=max(Period_Week_Counter))"}, OPE_WEK=, OPE_YY=>}STK_QT),GLOBAL_ITEM_ID,Yr_Wk_Frcst))



I need edit below expression to retrieve maximum value 19.3 of Expression number 2:

(sum({<Period_Week_Counter={">=$(=max(Period_Week_Counter)-2) <$(=max(Period_Week_Counter)+10)"}, OPE_WEK=, OPE_YY=>}Aggr(sum({<Period_Week_Counter={">=$(=max(Period_Week_Counter)-2) <$(=max(Period_Week_Counter)+10)"}, OPE_WEK=, OPE_YY=>}STK_QT),GLOBAL_ITEM_ID,Yr_Wk_Frcst))/sum({<Period_Week_Counter={">=$(=max(Period_Week_Counter)-2) <$(=max(Period_Week_Counter)+10)"}, OPE_WEK=, OPE_YY=>}Aggr(sum({<Period_Week_Counter={">=$(=max(Period_Week_Counter)-2) <$(=max(Period_Week_Counter)+10)"}, OPE_WEK=, OPE_YY=>}SHIPMENT_AVG_3_WEEKS),GLOBAL_ITEM_ID,Yr_Wk_Frcst)))*5


Can you please help?

22 Replies
Not applicable
Author

Yes both your last expressions return the value 30.7.

Your last expression is almost similar to the expression which produces value 27.6

I did several trials by editing it a bit and removing the "+ 10" from the period_counter in the condition and added aggregation by GLOBAL_ITEM_ID,Yr_Wk_Frcst, Country. THen it produced the correct value of 27.6

Next im trying to obtain the same max values for the future period from max(Period_Week_Counter) till the max number of weeks available and this period is associated with a different set of KPIs in the same graph that is why they are of different color.

I will create a different discussion thread for this hehe

Again many thanks to you guys and have a great day!

swuehl
MVP
MVP

Have a nice day, too.

If you create a new thread, please try to add a small sample application.

It's much easier to help  having the full range of information (am I repeating myself ).

sunny_talwar

Just to reiterate Stefan's words, sample is the best way to get fastest solutions to your problems. Look at some of these threads:

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