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Hi
I wonder if it's possible in a scatter plot the line : Y = X to share my plot thanks to the first diagonal line.
thanks for any help
Jean-Jacques
 
					
				
		
 Christian_Lauri
		
			Christian_LauriHi Jean-Jacques,
There is a fairly simple solution to your problem; you add a linear reference line to a fouth expression. In an XY plot, the first expression represents the X-axist, the second the Y axis and the third the size.
If you add a fourth expression that is a copy of the first, i.e. the x axis it will not be visible, but it is part of the solution. When you add a liniar reference line to the fourth expression, it will be drawn as X = Y as that is its expression.
Hope this helps,
Christian
 
					
				
		
Hi, does anyone know how to do a diagonal reference line in a scatter chart?
 
					
				
		
 pover
		
			pover
		
		
		
		
		
		
		
		
	
			
		
		
			
					
		Here are some X=Y Diagonal Lines in a Scatter Plot. I'm going to keep working on it, but right now for it to work you need to have a point selected that is at (0,0) for it to work, but if you naturally don't have this, you should be able to generate it in the script.
Regards.
 
					
				
		
 Christian_Lauri
		
			Christian_LauriHi Jean-Jacques,
There is a fairly simple solution to your problem; you add a linear reference line to a fouth expression. In an XY plot, the first expression represents the X-axist, the second the Y axis and the third the size.
If you add a fourth expression that is a copy of the first, i.e. the x axis it will not be visible, but it is part of the solution. When you add a liniar reference line to the fourth expression, it will be drawn as X = Y as that is its expression.
Hope this helps,
Christian
 
					
				
		
Thanks Christian!
Brilliant solution! This really helped me as well!
/Elsy
 
					
				
		
Waou ! very tricky !
thanks Christian ! it's nice to wait almost 2 years for a such answer.
JJ
 
					
				
		
 clisboa_noesis
		
			clisboa_noesis
		
		
		
		
		
		
		
		
	
			
		
		
			
					
		Hi,
I know it's been more than a year but...
Just a hint, if you show the equation for the linear line you can see that it's not exactly X=Y but close enough (y = 1x+1.81e-12 in my case).
Regards,
Carlos
 
					
				
		
Hi Christian,
It's working well.
Thanks!!!!
 
					
				
		
Thanks for this solution. Exactly what I needed!
 
					
				
		
 Christian_Lauri
		
			Christian_LauriI am glad to hear, Lorna! Thank you!
