Unlock a world of possibilities! Login now and discover the exclusive benefits awaiting you.
Hi All,
I have a table called equipment and i need one more date column through loop lets say
ColumnA ColumnB ColumnC NewDateColumn
1 a 1234 3-Apr-2014
2 b 5678 3-Apr-2014
3 c 9876 3-Apr-2014
1 a 1234 4- Apr-2014
2 b 5678 4- Apr-2014
3 c 9876 4- Apr-2014
1 a 1234 5- Apr-2014
2 b 5678 5- Apr-2014
3 c 9876 5- Apr-2014
Basically I should have 3 days of date generated for the entire data available in my Table. Lets say for entire data available in the table it should have 3-Apr-2014 and similarly the available data in table should have 4-Apr-2014.Same follows for 5-Apr-2014.
Any help would be appreciated.
Thanks in advance.
Ahh, I missed the actual issue, it is not about format but the loop variable.
Try:
For i = 0 to (vMax_Equ -vMin_Equ -1 )
Or,
For i = 0 to ($(vMax_Equ) - $(vMin_Equ) -1)
Dear Lavanya,
Seems that you need just create a pivot table with Date as a first Dimension, but...
Could you provide result tables?
Thanks
Andrei
Can you share any sample data for this and let me know how you create a NewDateColumn column in the table
In script,
Data:
Load * inline [
ColumnA, ColumnB, ColumnC
1, a, 1234
2, b, 5678
3, c, 9876
];
left join (Data)
load * inline [
NewDate
3-April-2014
4-April-2014
5-April-2014
];
flipside
May be like attached sample:
Let count=3;
Let StartDate=Num(Date#('3-4-2014', 'DD-MM-YYYY'));For i=0 to $(count)-1
Load
*,
Date($(StartDate)+$(i)) as Date
;
Load * Inline [
ColumnA, ColumnB, ColumnC
1, a, 1234
2, b, 5678
3, c, 9876];
Next i ;
Hi All,
Thanks for your quick response.
Let vMin_Equ = Today();
Let vMax_Equ = Date(Today()+5);
For i =vMin_Equ to vMax_Equ
vDate = Date(vMin_Equ+$(i));
Equipment:
Load *,
1 as dummy,
('$(vDate)') as UI_Date
Resident EQUIPMENT;
Next
DROP Table EQUIPMENT;
When I run this code i am not able to see the UI_Date Field having the values 3-Apr,4-Apr,5-Apr. Instaed i see the below data in UI_Date.
UI_Date 06/07/2128 07/07/2128 08/07/2128 09/07/2128 10/07/2128 11/07/2128 |
---|
But if i look at variable overview i see the values of
vMin_Equ = 3-Apr-2014
vMax_Equ = 8-Apr-2014.
Kindly suggestion what is causing the problem.
Thanks in advance.
Hi,
Could you please tell if i dnt want to use the Inline table and make the script to pick the dates automatically from today() to today()+5 days in the inline table.
Thanks in advance.
Try:
Date('$(vDate)' , 'DD-MMM-YYYY') as UI_Date
Tried but No Luck
Not sure what could be the reason of seeing different values in Variable Overview and in the Newly created field in backend..
In Variable Overview I am able to see the corect value for Vmin_Equ = 03-Apr and Vamx=04-Apr.