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draghici1109
Creator
Creator

Using max function deliver null values

Greeting community!

I use the min() function and it delivers me NULLS instead of numeric values. I do not have a clue, why this behavior.

Here are the details:

I want to read the followinf qvd file called HRP1001FZ2.qvd.

Hier is a sample of its content:

%key2;PERNR;PROZT;%key
00000188-0;00000188;0;00000008
00032020-100;00032020;100;30008268
00032032-100;00032032;100;30007087
00032044-100;00032044;100;30001537
00032056-100;00032056;100;30001808
00032068-100;00032068;100;30002200
00032111-100;00032111;100;30004052
00032123-100;00032123;100;30006532
00032159-100;00032159;100;30002201

10001348-50;10001348;50;30001626
10001348-50;10001348;50;30001623

00339660-50;00339660;50;30003234
00339660-50;00339660;50;30001770

10000998-100;10000998;100;30005927
10000998-100;10000998;100;30005929

In this file, I have some double records having the same PERNR. I want to use the min() function over the last field %key, and I get as results NULLs in this field.

Here the code:

HRP1001FZ3:
LOAD
PERNR,
min(%key)
FROM [..\DATA_20\HRP1001FZ2.qvd] (qvd)
Group by PERNR
;

Store [HRP1001FZ3] into [..\DATA_20\HRP1001FZ3.qvd](qvd);
Drop Table [HRP1001FZ3];

I do not understand why I get NULLs in the last column, see next screenshot:

 

draghici1109_0-1619697847353.png

 

Does anyone has an idea what goes wrong?

Thank you in advance!

Alexandru

 

P.S.: I used also max(num(%key)) but got the same results...

Alexandru Draghici
BICC at Komm.ONE
Labels (2)
1 Solution

Accepted Solutions
draghici1109
Creator
Creator
Author

found myself the solution:

 

using min(num#(%key)) solved the problem!

Alexandru Draghici
BICC at Komm.ONE

View solution in original post

1 Reply
draghici1109
Creator
Creator
Author

found myself the solution:

 

using min(num#(%key)) solved the problem!

Alexandru Draghici
BICC at Komm.ONE