Unlock a world of possibilities! Login now and discover the exclusive benefits awaiting you.
 paolojolly
		
			paolojolly
		
		
		
		
		
		
		
		
	
			
		
		
			
					
		Hi, i need help in qlikview document for calculating the count occurrences of min value in pivot chart
In the attached document for calculating the occurrences of the minimum price for C_FAMIGLIA_RIL field i use
sum( if( W_PRZ_PUBBL_FAM = Aggr( Min(W_PRZ_PUBBL_FAM) , C_FAMIGLIA_RIL) , 1 , 0))
but it is not working properly
can someone help me?
thanks
 sunny_talwar
		
			sunny_talwar
		
		
		
		
		
		
		
		
	
			
		
		
			
					
		May be this:
=Sum(Aggr(If(W_PRZ_PUBBL_FAM = Min(TOTAL <C_FAMIGLIA_RIL> W_PRZ_PUBBL_FAM), 1, 0), C_FAMIGLIA_RIL, C_NEGOZIO))
Are you expecting 2 for 00A and 0 for 00B, Or what
If yes, You can use this
=count({<W_PRZ_PUBBL_FAM = {'=$(Min(W_PRZ_PUBBL_FAM))'}>}C_FAMIGLIA_RIL)
If you are expecting 24, 5 then might Adam Solution Work
=count({<W_PRZ_PUBBL_FAM = {'=Min(W_PRZ_PUBBL_FAM)'}>}C_FAMIGLIA_RIL)
OR If you are expecting 1, 1 Then you can use DISTINCT
=count({<W_PRZ_PUBBL_FAM = {'=$(Min(W_PRZ_PUBBL_FAM))'}>} DISTINCT C_FAMIGLIA_RIL)
 paolojolly
		
			paolojolly
		
		
		
		
		
		
		
		
	
			
		
		
			
					
		i'm expecting
| C_FAMIGLIA_RIL | min value of W_PRZ_PUBBL_FAM | occurrences of min value | 
| 00A | 0,69 | 2 | 
| 00B | 0,75 | 1 | 
thanks
 
					
				
		
 adamdavi3s
		
			adamdavi3s
		
		
		
		
		
		
		
		
	
			
		
		
			
					
		I deleted my answer as looking at the data it was not correct.
I think 2 and 1 is the correct answer?
 paolojolly
		
			paolojolly
		
		
		
		
		
		
		
		
	
			
		
		
			
					
		yes
thanks
 sunny_talwar
		
			sunny_talwar
		
		
		
		
		
		
		
		
	
			
		
		
			
					
		May be this:
=Sum(Aggr(If(W_PRZ_PUBBL_FAM = Min(TOTAL <C_FAMIGLIA_RIL> W_PRZ_PUBBL_FAM), 1, 0), C_FAMIGLIA_RIL, C_NEGOZIO))
 paolojolly
		
			paolojolly
		
		
		
		
		
		
		
		
	
			
		
		
			
					
		It works perfectly
thank you so much
 sunny_talwar
		
			sunny_talwar
		
		
		
		
		
		
		
		
	
			
		
		
			
					
		No problem at all 
