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tincholiver
Creator III
Creator III

time format

Hi everyone, i have some problems with time format:

xls file has next header

Fecha08:0008:3009:0009:3010:0010:30
01/08/20208059420852
02/08/2020621267366314
03/08/2020434119434260
04/08/2020299321425822
05/08/202046394539793

 

but when i want to load i get next data

 

LOAD
Fecha,
[0.33333333333333331],
[0.35416666666666669],
[0.375],
[0.39583333333333298],
[0.41666666666666702],
[0.4375],
FROM...

 

i tried with Time and Time# function but not works.

 

any idea??

 

thanks a lot!

1 Solution

Accepted Solutions
QFabian
Specialist III
Specialist III

Hi @tincholiver , here an example that i made with yor data, the words in red are the new ones :

The script transforms the Time columns in rows, using crosstable() function.

Then cratres a valid num time format, replacing a character from '.' to ','.

Aux:
CrossTable(Time, Data)
LOAD Fecha,
[0.33333333333333331],
[0.35416666666666669],
[0.375],
[0.39583333333333331],
[0.41666666666666669],
[0.4375]
FROM
[..\Desktop\Libro1.xlsx]
(ooxml, embedded labels, table is Hoja1);

Data:
Load
Fecha,
replace(Time,'.',',') as Hora,
Data
Resident Aux;
drop table Aux;

 

 

QFabian

View solution in original post

2 Replies
QFabian
Specialist III
Specialist III

Hi @tincholiver , here an example that i made with yor data, the words in red are the new ones :

The script transforms the Time columns in rows, using crosstable() function.

Then cratres a valid num time format, replacing a character from '.' to ','.

Aux:
CrossTable(Time, Data)
LOAD Fecha,
[0.33333333333333331],
[0.35416666666666669],
[0.375],
[0.39583333333333331],
[0.41666666666666669],
[0.4375]
FROM
[..\Desktop\Libro1.xlsx]
(ooxml, embedded labels, table is Hoja1);

Data:
Load
Fecha,
replace(Time,'.',',') as Hora,
Data
Resident Aux;
drop table Aux;

 

 

QFabian
tincholiver
Creator III
Creator III
Author

thanks Fabian!! 

it works!

Regards