Create Separate Output File based on Input File Name Identifier
Hi All,
I am trying to implement Encryption Decryption of Context File. I am able to do that. Now challenge is I have 11 DataSources. So 11 Context File is there. I am trying to create a Single Job which will run at first and will encrypt all the Context Files. Requirement is if any Context File is having Name as File_A.txt then encrypted Context File will generate with File_A.txt. Can it be achiveble? @TRF, @rhall, @vboppudi, @manodwhb
My Question is How to generate Output File based on my Input FileName Pattern. For E.G if I have 11 Files in a Location and iterating it in a FileList I want to generate a Output .txt File for each Pattern Matching Up with Input FileName. So if My Source FileNames are Abhijit_File1_DS1.txt,Abhijit_File1_DS2.txt then Output File will be generating based on the _DS value present. So If DS1 is xxx and DS2 will be yyy File1 will be having Name as ----_xxx.txt.
Connect a tJava after tFileList and use the String.split() method to get the parts of the tFileList_1_CURRENT_FILE and generate the desired filename for each output file. The result should be stored into a global or context variable.
