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hi
Please see the below table
name | id | number | level |
teh | 1 | 0 | A |
teh | 2 | 0 | A |
teh | 3 | 1 | A |
teh | 4 | 1 | A |
SO | 8 | 1 | A |
SO | 9 | 1 | B |
SO | 12 | 1 | C |
teh | 15 | 1 | B |
teh | 19 | 1 | B |
SO | 20 | 1 | C |
teh | 25 | 1 | B |
SO | 26 | 1 | C |
I want the last level of each name (largest id)
I want this:
NAME | RESULT |
teh | B |
so | C |
so I use this formula
=firstsortedvalue(level, -id, 1) and its ok !
but i want to use variable! vll=firstsortedvalue(level, -id, 1) and this variable return C for both names and this is wrong answer!
please help me 🙂
I'd give it a whirl with using a string variable and evaluating it within the expression. No idea if that'd work, but that's my best bet.
firstsortedvalue(level, -id, 1)
with no equal sign (so it's a string, not a formula)
Then, =$(vLL) in your expression.
Using your formula on your data returned this...
YES but I used variable ! vLL=firstsortedvalue(level, -id, 1) and use a variable in expressions
it returns C for both names!
how can I use a variable instead of write a formula?
No idea! If you'd asked that in the first place I would have left this for someone else to try and answer... (;
I appreciate your attention 🙂
I'd give it a whirl with using a string variable and evaluating it within the expression. No idea if that'd work, but that's my best bet.
firstsortedvalue(level, -id, 1)
with no equal sign (so it's a string, not a formula)
Then, =$(vLL) in your expression.
THX A LOT 🙂