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What is the function used to show 2.3 as 3.
Round(2.3)
Regards.
Siva
hi
use round of function...
round( x [ , base [ , offset ]])
Rounding of x upwards or downwards to the nearest multiple of base with an offset of offset. The result is a number. If x is exactly in the middle of an interval, it is rounded upwards.
Examples:
round( 2.4 ) returns 2
round( 2.6 ) returns 3
round( 2.5 ) returns 3
round( 3.88 , 0.1 ) returns 3.9
round( 3.88 , 5 ) returns 5
round( 1.1 , 1 , 0.5 ) returns 1.5
frac() returns the decimal part
floor() returns the integer part
frac(x)+floor(x) = x
Fabrice
=Ceil(2.3) try this
hi try this
ceil( 2.3 ) returns 3
hi Renuka,
i think u got Answer for your question so please mark this question As answered by choosing Correct answer
so it will help others also
those who are searching for same type Of Qustions
Hi,
Try
Ceil(Number)
Regards,
Jagan.
Hi Renuka,
Try this :
Ceil(Your_Field) as Your_number
Thanks
AS