SSN number and age (DDMMYYXXXXX) age?

[anitamelbye]

MayHello,

I have tried to find an answer to my question, but I can not find any good solution. Maybe someone can help me?

Our SSN# is 11 digits and the first six numbers is our birthdate. Eks. DDMMYYXXXXX.

How can I easily find the age from this SSN#? Is it possible?

Is it even possible to find a solution if a person is born March 1. 2001? SSN# will be 010301XXXXX

I am so very greatful for a little help with this challenge

THANK YOU in advance!
🙂

Best regards

Anita
,

[MK_QSL]

Date(Date#(Left(SSN#,6),'DDMMYY')) as YourDateField

[#3]

Then if you want age from this, you can just use

Age(today(),Date(Date#(Left(SSN#,6),'DDMMYY'))) as YourAgeField

[anitamelbye]

Thank you for trying to help, but it does not give me the right result..

When the SSN# begins with a '0' the results in age is -.

When the SSN# begins with 1-9, the results is 44 for all the emplyees 🙂

Any other tips?

[#5]

Maybe the formats then try

Age(Date(today(),'DDMMYY'),Date#(Left(SSN#,6),'DDMMYY'))

failing that post up the example and can then take a better look

[anitamelbye]

Thank you again for trying to help, but I am sorry, it still does not work.

I have tried to simplify my data, I hope you understand 🙂

Se Attached files .xls (with the SSN#) and .qvw

How can I find the right age? 🙂

[#7 · Accepted solution]

Ah I see, looks like you have a couple of issues going on here, the leading zero dropping and also the year being interpreted as this century. Please see attached, I have had to create a new field in your excel to define the century for each SSN, as you could have a mix in there.

hope that helps

Joe

[puttemans]

Hello Anita,

I've found a solution, be it through a pass-by.

100:

LOAD * inline [ number
010196-48911
010262-44699
130388-46781
130449-30794
210154-28721
210186-45383
210255-47974
210284-34909
210379-38391
210479-39760
210556-38958
210576-45900
];


200:

LOAD*,
2014-year2 as age;

LOAD*,
year&right(date,2) as year2;

LOAD *,
if(right(date,2)<= 15 ,20, 19) as year;

LOAD *,
date#(left(number,6),'DDMMYY') as date
Resident 100;
drop table 100;

Kind regards,