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Hi! Please I need your help, I would like to transform my formula to time hh:mm:ss. I've tried with time, Interval and TimeStamp, but its not working. I´ve attached my qv file.
Thanks!
Hi,
Try with this using mod function
Time#(Floor(SumOfSum_DiferenciaCL/60) & ':'& Mod(SumOfSum_DiferenciaCL,60),'h:m')
Celambarasan
Hi,
what is the field name that you are trying to convert?
Hi,
The Expression is (SumOfSum_DiferenciaCL/60) & ':'& ((SumOfSum_DiferenciaCL/60) - (SumOfSum_DiferenciaCL/60)*60). And this I need to pass To Time. For example: Sumof sum 18 that number I have to convert to time. In my Excel file I have: =INT(C2/60)&":"&INT(((C2/60)-INT(C2/60))*60),
so the number 18 is converted to 0:18.
Hi,
Did you tried with Time#?
Time#(SumOfSum_DiferenciaCL/60) & ':'& ((SumOfSum_DiferenciaCL/60) - (SumOfSum_DiferenciaCL/60)*60,'h:m')
Hope it helps
Celambarasan
Hi, thanks for your reply but Still is not working
Time#(SumOfSum_DiferenciaCL/60,'h:m') & ':'& ((SumOfSum_DiferenciaCL/60) - (SumOfSum_DiferenciaCL/60)*60).
Hi,
Paranthesis problem in previous post check the below expression.
Time#((SumOfSum_DiferenciaCL/60) & ':'& ((SumOfSum_DiferenciaCL/60) - (SumOfSum_DiferenciaCL/60)*60),'h:m')
Celambarasan
Hi, Still not working. I´ve tried with format number but nothing happened.
Any help?
Thanks!
Hi
I think it returns decimal values.
Check with this
Time#(Floor(SumOfSum_DiferenciaCL/60) & ':'& Floor((SumOfSum_DiferenciaCL/60) - (SumOfSum_DiferenciaCL/60)*60),'h:m')
Hope it helps
Celambarasan
Thank you for your reply. Almost ready. but I think is not working yet. The idea is emule the excel file. I´ve attached the excel file for better comprehenssion.
Thanks