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z-score in table object

Dear all,

I want to create a table - see image - which show the z-scores for each company (instead of the normal scoring which is currently in the table). Does somebody know the expression to get this done? I can't find it.

ps. z-scores describe the distance of the company score to the mean, expressed in standarddeviation.

Schermafbeelding 2011-11-30 om 21.00.36.png

1 Solution

Accepted Solutions
johnw
Champion III
Champion III

This would be easier with an example file to play with, but let's see.  I'm guessing that each company has a single score?  So the mean (since you want it in the chart) is probably:

avg(total Score)

And the standard deviation is probably:

stdev(total Score)

And so your z-score would probably be:

(Score - avg(total Score))/stdev(total Score)

View solution in original post

3 Replies
johnw
Champion III
Champion III

This would be easier with an example file to play with, but let's see.  I'm guessing that each company has a single score?  So the mean (since you want it in the chart) is probably:

avg(total Score)

And the standard deviation is probably:

stdev(total Score)

And so your z-score would probably be:

(Score - avg(total Score))/stdev(total Score)

Not applicable
Author

Fantastic John, It works. Thanks for quick response.

jmmayoral3
Creator
Creator

Very good answer and very simple.

I have espent a lot of time searching a function which does a zcore in the documentation ofSense.