tjava handle multiple if-else

[talend777]

we have files that we are reading and trying to rename in some scenarios and below code works..

files --

• data/file1.csv --> after renaming
  data/datefolder=2025-01-01/file.csv
• data/file2_2025-01-01.csv --> after renaming renaming
  data/datefolder=2025-01-01/file2_2025-01-01.csv

String regex = "[0-9]{4}[_-][0-9]{2}[_-][0-9]{2}";

java.util.regex.Matcher m = java.util.regex.Pattern.compile(regex).matcher(context.CurrentFileName);

if (m.find()) {           
            context.CurrentFileDate = "datefolder="+(m.group(0).trim().substring(0,4))+"-"+(m.group(0).trim().substring(5,7))+"-"+(m.group(0).trim().substring(8,10));            
        } else {
            context.CurrentFileDate = "datefolder="+formattedDate;                    }

        
        

now we are getting interesting file-names and needed some help how i can modify above if-else statement so it can work.

files --

• data/file1.csv --> after renaming data/datefolder=2025-01-01/file.csv
• data/file2_2025-01-01.csv --> after renaming renaming data/datefolder=2025-01-01/file2_2025-01-01.csv
• data/YYYY=2029/file3.csv --> after renaming data/datefolder=2029-01-01/file3.csv
• • (SO If there is a prefix of YYYY=2029, modify datefolder to get year from yyyy datefolder=2029-01-01 )
• data/YYYY=2029/MM=03/file4.csv --> after renaming data/datefolder=2029-03-01/file4.csv
• • (SO If there is a prefix of YYYY=2029 & MM=03, modify datefolder to get year from yyyy AND Month from mm, so datefolder=2029-03-01 )
• data/YYYY=2029/MM=04/DD=22/file5.csv --> after renaming data/datefolder=2029-04-22/file5.csv
• • (SO If there is a prefix of YYYY=2029 & MM=03, modify datefolder to get year from yyyy AND Month from mm and day from dd, so datefolder=2029-04-22 )

any suggestion how to modify above if-else statement ? since matcher in java can only find based on regex, in what i tried so far .

[gouravdubey5]

Hello,

Instead of extending multiple if-else blocks, the recommended approach is to extract YYYY / MM / DD independently using regex, then build the date based on what is present. This keeps the logic simple and scalable.

Example (tJava-compatible):

String filePath = context.CurrentFileName;

String year = null;
String month = "01";
String day = "01";

// Match YYYY=2029
java.util.regex.Matcher y =
java.util.regex.Pattern.compile("YYYY=(\\d{4})").matcher(filePath);
if (y.find()) {
year = y.group(1);
}

// Match MM=03
java.util.regex.Matcher m =
java.util.regex.Pattern.compile("MM=(\\d{2})").matcher(filePath);
if (m.find()) {
month = m.group(1);
}

// Match DD=22
java.util.regex.Matcher d =
java.util.regex.Pattern.compile("DD=(\\d{2})").matcher(filePath);
if (d.find()) {
day = d.group(1);
}

// Fallback: date inside filename (2025-01-01 or 2025_01_01)
if (year == null) {
java.util.regex.Matcher f =
java.util.regex.Pattern.compile("(\\d{4})[_-](\\d{2})[_-](\\d{2})")
.matcher(filePath);
if (f.find()) {
year = f.group(1);
month = f.group(2);
day = f.group(3);
}
}

// Final fallback
if (year == null) {
context.CurrentFileDate = "datefolder=" + formattedDate;
} else {
context.CurrentFileDate =
"datefolder=" + year + "-" + month + "-" + day;
}

Why this works well:

Avoids deep if-else chains

Handles partial paths (YYYY, YYYY/MM, YYYY/MM/DD)

Safely defaults missing month/day to 01

Still supports dates embedded in filenames

Best practice:
When filename patterns evolve, extract each date component independently and compose the final value, rather than trying to match all cases in a single regex.

Thanks,

Gourav

[gouravdubey5]

Hi,

This approach also makes it easy to support future filename or folder variations, since each date component is handled independently. Missing values safely default to 01, avoiding additional conditional logic.

If this solution addresses the requirement, please mark it as Accepted Solution.

Thanks,
Gourav