I have a text file that has a string column with a datetime formatted as "MM/dd/yyyy HH:mm:ss aa" or "02/18/2009 03:30:00 AM" I am trying to extract the Time and convert it to a 24 Hour Date field. So far in Tmap I have used the following syntax to extract the time data as a date field but it is still in a 12 hour format. Is there any way to convert it to 24 hour format?
It seems that no matter what I try use Talend.ParseDate against a STRING in the format of "MM/dd/yyyy HH:mm:ss aa" or "2/12/2009 02:12:00 PM" it converts the date to AM.
I have tried this numerous ways. Am I missing something?
TalendDate.getPartOfDate("HOUR",TalendDate.parseDate("yyyy-MM-dd HH:mm:ss",TalendDate.formatDate("yyyy-MM-dd hh:mm:ss",row1.HOUR))) can anyone help me out please what wrong in this code, i am trying to fetch 24hrs day format from the above code.
My output looks like 0 to 12 here is in below , my requirement is the HOUR column have to be 0 to 24 like minutes 0 to 59. I am new to Talend and i did not find any documentation forum how to convert the time format to 24 hrs
Could you please give us your input column? Is it "Date" type? Elaborating your case with an example with input and expected output values will be preferred.
The method should be: TalendDate.getPartOfDate(String, Date):int Best regards Sabrina
Hello Geeks, Please help I am struggling , new to talend I have a input string as utcStartTime which has a value 1443696342801 I want to convert this into date something like this : 01-01-1970 11:52:39
tried many things new java.util.Date(Long)(row1.HIREDATEe*1000)) but still unable to do so PLease helppp me many thanks
